Today we had have corrected the mutation homework.

Then we had corrected some genetic exercises:

4        A green-red colour-blind woman marries a normal vision male.

Xa= not afected cromosome.Is dominant.

(Then, if it is dominant why don´t you write it with capital letters??, please change it.) -fernando-

XA=afected one.

A)    100% of sons afected.

B)    0% of daughtes afected.

C)    100% of daughtes will be carrieres.

7        An albino man marries a normaly-pigmented woman who had an albino mother.

H= not albino, dominant.

h= albino,recesive.

The couple will have 50% of having an albino children and 50% of having a normal one.

Explain: how do you know that this woman is heterozygous?

8        A colour-blind man marries a woman with normal vision. Her mother is colour blind.

Xa= not afected cromosome.Is dominant.

XA=afected one.

(As in the first exercise, if it is dominant why don´t you write it with capital letters??, please change it.) -fernando-

The mother of the woman is colour-blind so shi she is XaXA. Good, well explained this time.

Their children will be : 50% afected

50% normal

Lack of a Punnett square here to clarify it all.

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